Follow the story. Try a proof. Let curiosity choose how deep you go.
Walk in through the manga: seventeen chapters, sixty-four pocket pebbles, zero required formulas. The Lean source stays behind glass until you ask for it.
Straight to the mathematicsBegin at the proof map — thousands of named theorems — then climb the full ladder from clock inverses to R = T. The story keeps telling itself beside you; it will keep you honest.
Made for company: one reader who loves math and one who does not — one sofa. Whatever each of you finds carries over to the tea salon.
Seventeen chapters, one extraordinary argument. One small discovery is enough for today.
Pip’s rule: mistakes are clues. Every chapter is open, and every question allows another try.
Why the curve’s arithmetic cannot split the wrong way.
Search the local catalogue in English or Japanese. Major landmarks have Japanese titles. Open the full original proof on GitHub for the complete context.
The claim: this knot of symmetry has no loose strand — no straight line of threads that every shuffle leaves alone. Assuming the strand exists is the wrong-but-useful move. The exits are sealed one by one: the small-prime door, the large-prime door, and finally the no-stable-line argument, so reducibility destroys itself.
Annotated original · not a live Lean statePoint to a story clue or a highlighted term to connect the two.
Try this logical move →Source: anthropics/fermats-last-theorem @ aa2d8b3. Upstream reports verification; this reader has not independently rebuilt the project. Manga explanations are not formal proofs.
Source license & attributionPip proposes cutting the problem in half. The symmetries object.
The Frey package gave us a curve. We now inspect a representation attached to it. “Irreducible” concerns invariant subspaces of that representation, not whether the drawn curve can be cut with scissors.
These links explain the reading route. A story analogy is not a proof of this theorem.
Already familiar? Keep reading. Otherwise, open a word or follow the prerequisites from the beginning.
Story → proofPip’s scissors propose a split. The proof temporarily assumes reducibility to derive a contradiction.
Assume the forbidden splitby_contra hredStory → proofA strand that stayed on its own would be a Galois-stable line. The connected drawing illustrates its role, not its definition.
The forbidden stable lineHasGaloisStableCofixedLineStory → proofThe blocked exits are the prime cases where that stable line is ruled out. This source term closes the large-prime exit.
Close the large-prime exitFreyPackage.frey_no_cofixed_largeStory → proofThe intact circle is the irreducibility conclusion. The remaining branch uses the no-stable-line argument.
Use the no-line argumentmazurM3asmB_of_no_cofixedThe claim: this knot of symmetry has no loose strand — no straight line of threads that every shuffle leaves alone. Assuming the strand exists is the wrong-but-useful move. The exits are sealed one by one: the small-prime door, the large-prime door, and finally the no-stable-line argument, so reducibility destroys itself.
The story and source are readable here. Enable JavaScript to edit proofs, try quizzes, and explore the interactive map.
Short scenes. Real logical goals. A pigeon who is very invested in your success.
Opening the casebook…
The scissors incident
Start with the cake-scale story. You only need to read one small piece at a time. If you are in the Fermat story, start with Story depth, then the words listed before the chapter.
You do not need to know Lean, symbols or university mathematics to begin. Definitions come first in the small stories.
Look at the small example before the general formula. Ask what changed and what stayed the same.
Close this panel to return to the exact place you were reading. These are prepared hints for this page.
Start with the first small story →