Build the idea in three steps
- On a clock with nine positions, every integer has a remainder, and multiplication respects remainders.
- Whatever integer n is, its cube reduces on this clock to one of just three values: 0, 1 or 8. A number not divisible by three always avoids the 0 slot and lands on 1 or 8.
- The theorem collects the payoff: if 3 divides none of a, b and c, then a ^ 3 + b ^ 3 ≠ c ^ 3 — two residues from {1, 8} cannot sum to another.
A small example
The clock keeps cubes honest: 4³ = 64 leaves remainder 1, and 2³ leaves 8. Summing any two of {1, 8} gives 2, 0 or 7 — never 1 or 8, so no cube of a nonmultiple of three can stand at the far end of an equality.